$$X[k] = \begin{bmatrix} 10 & -2+j2 & -2 & -2-j2 \end{bmatrix}$$
$$X[k_1, k_2] = \begin{bmatrix} 10 & -2 \ -2 & -2 \end{bmatrix}$$ $$X[k] = \begin{bmatrix} 10 & -2+j2 & -2
(b) The odd part of the signal $x[n] = \cos(0.5\pi n)$ is $x_o[n] = 0$. $$X[k] = \begin{bmatrix} 10 & -2+j2 & -2
The impulse response of the filter is:
(b) The maximum and minimum values that can be represented by 12-bit unsigned binary numbers are 4095 and 0, respectively. $$X[k] = \begin{bmatrix} 10 & -2+j2 & -2