Numerical Methods Madasmaths -

(a) Show that the Newton-Raphson iterative formula for this root is [ x_n+1 = x_n - \frac\ln(x_n+2) - x_n\frac1x_n+2 - 1. ]

In the polished world of pure mathematics, answers are often exact: ( \sqrt2 ), ( \pi ), or a neatly factored root of a polynomial. But the real world—physics, engineering, finance—rarely offers such tidy solutions. It demands approximations. It demands numerical methods. numerical methods madasmaths

Consider this gem from a past MADASMATHS worksheet: "The equation ( e^x - 3x = 0 ) has a root in ( [0, 0.5] ). Perform one bisection iteration. What is the maximum possible error in your approximation after this iteration?" The answer: half the interval width (0.25). But the follow-up asks: "How many iterations are needed to guarantee an error less than ( 10^-6 )? Write your answer as an inequality." (a) Show that the Newton-Raphson iterative formula for